Optimal. Leaf size=137 \[ a^3 A x+\frac {b \left (8 a^2 B+9 a A b+2 b^2 B\right ) \tan (c+d x)}{3 d}+\frac {\left (2 a^3 B+6 a^2 A b+3 a b^2 B+A b^3\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {b^2 (5 a B+3 A b) \tan (c+d x) \sec (c+d x)}{6 d}+\frac {b B \tan (c+d x) (a+b \sec (c+d x))^2}{3 d} \]
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Rubi [A] time = 0.19, antiderivative size = 137, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 23, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {3918, 4048, 3770, 3767, 8} \[ \frac {b \left (8 a^2 B+9 a A b+2 b^2 B\right ) \tan (c+d x)}{3 d}+\frac {\left (6 a^2 A b+2 a^3 B+3 a b^2 B+A b^3\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+a^3 A x+\frac {b^2 (5 a B+3 A b) \tan (c+d x) \sec (c+d x)}{6 d}+\frac {b B \tan (c+d x) (a+b \sec (c+d x))^2}{3 d} \]
Antiderivative was successfully verified.
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Rule 8
Rule 3767
Rule 3770
Rule 3918
Rule 4048
Rubi steps
\begin {align*} \int (a+b \sec (c+d x))^3 (A+B \sec (c+d x)) \, dx &=\frac {b B (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac {1}{3} \int (a+b \sec (c+d x)) \left (3 a^2 A+\left (6 a A b+3 a^2 B+2 b^2 B\right ) \sec (c+d x)+b (3 A b+5 a B) \sec ^2(c+d x)\right ) \, dx\\ &=\frac {b^2 (3 A b+5 a B) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {b B (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac {1}{6} \int \left (6 a^3 A+3 \left (6 a^2 A b+A b^3+2 a^3 B+3 a b^2 B\right ) \sec (c+d x)+2 b \left (9 a A b+8 a^2 B+2 b^2 B\right ) \sec ^2(c+d x)\right ) \, dx\\ &=a^3 A x+\frac {b^2 (3 A b+5 a B) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {b B (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}+\frac {1}{3} \left (b \left (9 a A b+8 a^2 B+2 b^2 B\right )\right ) \int \sec ^2(c+d x) \, dx+\frac {1}{2} \left (6 a^2 A b+A b^3+2 a^3 B+3 a b^2 B\right ) \int \sec (c+d x) \, dx\\ &=a^3 A x+\frac {\left (6 a^2 A b+A b^3+2 a^3 B+3 a b^2 B\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {b^2 (3 A b+5 a B) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {b B (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}-\frac {\left (b \left (9 a A b+8 a^2 B+2 b^2 B\right )\right ) \operatorname {Subst}(\int 1 \, dx,x,-\tan (c+d x))}{3 d}\\ &=a^3 A x+\frac {\left (6 a^2 A b+A b^3+2 a^3 B+3 a b^2 B\right ) \tanh ^{-1}(\sin (c+d x))}{2 d}+\frac {b \left (9 a A b+8 a^2 B+2 b^2 B\right ) \tan (c+d x)}{3 d}+\frac {b^2 (3 A b+5 a B) \sec (c+d x) \tan (c+d x)}{6 d}+\frac {b B (a+b \sec (c+d x))^2 \tan (c+d x)}{3 d}\\ \end {align*}
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Mathematica [A] time = 0.59, size = 108, normalized size = 0.79 \[ \frac {6 a^3 A d x+3 b \tan (c+d x) \left (6 a^2 B+b (3 a B+A b) \sec (c+d x)+6 a A b+2 b^2 B\right )+3 \left (2 a^3 B+6 a^2 A b+3 a b^2 B+A b^3\right ) \tanh ^{-1}(\sin (c+d x))+2 b^3 B \tan ^3(c+d x)}{6 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.47, size = 189, normalized size = 1.38 \[ \frac {12 \, A a^{3} d x \cos \left (d x + c\right )^{3} + 3 \, {\left (2 \, B a^{3} + 6 \, A a^{2} b + 3 \, B a b^{2} + A b^{3}\right )} \cos \left (d x + c\right )^{3} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \, {\left (2 \, B a^{3} + 6 \, A a^{2} b + 3 \, B a b^{2} + A b^{3}\right )} \cos \left (d x + c\right )^{3} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, {\left (2 \, B b^{3} + 2 \, {\left (9 \, B a^{2} b + 9 \, A a b^{2} + 2 \, B b^{3}\right )} \cos \left (d x + c\right )^{2} + 3 \, {\left (3 \, B a b^{2} + A b^{3}\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{12 \, d \cos \left (d x + c\right )^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 0.65, size = 336, normalized size = 2.45 \[ \frac {6 \, {\left (d x + c\right )} A a^{3} + 3 \, {\left (2 \, B a^{3} + 6 \, A a^{2} b + 3 \, B a b^{2} + A b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 1 \right |}\right ) - 3 \, {\left (2 \, B a^{3} + 6 \, A a^{2} b + 3 \, B a b^{2} + A b^{3}\right )} \log \left ({\left | \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) - 1 \right |}\right ) - \frac {2 \, {\left (18 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 18 \, A a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 9 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 3 \, A b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} + 6 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5} - 36 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 36 \, A a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} - 4 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{3} + 18 \, B a^{2} b \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 18 \, A a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 9 \, B a b^{2} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 3 \, A b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right ) + 6 \, B b^{3} \tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )}}{{\left (\tan \left (\frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{2} - 1\right )}^{3}}}{6 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 1.18, size = 223, normalized size = 1.63 \[ a^{3} A x +\frac {A \,a^{3} c}{d}+\frac {a^{3} B \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {3 A \,a^{2} b \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {3 a^{2} b B \tan \left (d x +c \right )}{d}+\frac {3 A a \,b^{2} \tan \left (d x +c \right )}{d}+\frac {3 B a \,b^{2} \sec \left (d x +c \right ) \tan \left (d x +c \right )}{2 d}+\frac {3 B a \,b^{2} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2 d}+\frac {A \,b^{3} \sec \left (d x +c \right ) \tan \left (d x +c \right )}{2 d}+\frac {A \,b^{3} \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2 d}+\frac {2 b^{3} B \tan \left (d x +c \right )}{3 d}+\frac {b^{3} B \tan \left (d x +c \right ) \left (\sec ^{2}\left (d x +c \right )\right )}{3 d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.32, size = 202, normalized size = 1.47 \[ \frac {12 \, {\left (d x + c\right )} A a^{3} + 4 \, {\left (\tan \left (d x + c\right )^{3} + 3 \, \tan \left (d x + c\right )\right )} B b^{3} - 9 \, B a b^{2} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} - 3 \, A b^{3} {\left (\frac {2 \, \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1} - \log \left (\sin \left (d x + c\right ) + 1\right ) + \log \left (\sin \left (d x + c\right ) - 1\right )\right )} + 12 \, B a^{3} \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 36 \, A a^{2} b \log \left (\sec \left (d x + c\right ) + \tan \left (d x + c\right )\right ) + 36 \, B a^{2} b \tan \left (d x + c\right ) + 36 \, A a b^{2} \tan \left (d x + c\right )}{12 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.03, size = 526, normalized size = 3.84 \[ \frac {\frac {A\,b^3\,\sin \left (2\,c+2\,d\,x\right )}{4}+\frac {B\,b^3\,\sin \left (3\,c+3\,d\,x\right )}{6}+\frac {B\,b^3\,\sin \left (c+d\,x\right )}{2}+\frac {3\,A\,a\,b^2\,\sin \left (c+d\,x\right )}{4}+\frac {3\,B\,a^2\,b\,\sin \left (c+d\,x\right )}{4}+\frac {3\,A\,a^3\,\cos \left (c+d\,x\right )\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )}{2}-\frac {A\,b^3\,\cos \left (c+d\,x\right )\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,3{}\mathrm {i}}{4}-\frac {B\,a^3\,\cos \left (c+d\,x\right )\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,3{}\mathrm {i}}{2}+\frac {3\,A\,a\,b^2\,\sin \left (3\,c+3\,d\,x\right )}{4}+\frac {3\,B\,a\,b^2\,\sin \left (2\,c+2\,d\,x\right )}{4}+\frac {3\,B\,a^2\,b\,\sin \left (3\,c+3\,d\,x\right )}{4}+\frac {A\,a^3\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,\cos \left (3\,c+3\,d\,x\right )}{2}-\frac {A\,b^3\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,\cos \left (3\,c+3\,d\,x\right )\,1{}\mathrm {i}}{4}-\frac {B\,a^3\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,\cos \left (3\,c+3\,d\,x\right )\,1{}\mathrm {i}}{2}-\frac {A\,a^2\,b\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,\cos \left (3\,c+3\,d\,x\right )\,3{}\mathrm {i}}{2}-\frac {B\,a\,b^2\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,\cos \left (3\,c+3\,d\,x\right )\,3{}\mathrm {i}}{4}-\frac {A\,a^2\,b\,\cos \left (c+d\,x\right )\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,9{}\mathrm {i}}{2}-\frac {B\,a\,b^2\,\cos \left (c+d\,x\right )\,\mathrm {atan}\left (\frac {\sin \left (\frac {c}{2}+\frac {d\,x}{2}\right )\,1{}\mathrm {i}}{\cos \left (\frac {c}{2}+\frac {d\,x}{2}\right )}\right )\,9{}\mathrm {i}}{4}}{d\,\left (\frac {3\,\cos \left (c+d\,x\right )}{4}+\frac {\cos \left (3\,c+3\,d\,x\right )}{4}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \left (A + B \sec {\left (c + d x \right )}\right ) \left (a + b \sec {\left (c + d x \right )}\right )^{3}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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